Question

PLEASE ANYONE ANSWER

Answer 1

2x+2√6+3y²
⇒(√2x+√3 y)²         where x is in root and y is not



x²+y-z²-2xy
x²+y²-2xy-z²
(x-y)²-z²

x²-27x+176
x²-16x-11x+176        by spliting the middle term
x(x-16)-11(x-16)
(x-16)(x-11)
x=16 or 11