Math, asked by smritidas415, 8 days ago

please anyone answer me I need urgent ​

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Answers

Answered by ahbabu558
0

Answer:xXy=lcm×hcf

27/98=3/2×hcf

Hcf=27×98×2/3

Hcf=9/49

Step-by-step explanation:

Answered by MystícPhoeníx
7

Answer:

  • 9/49 is their required HCF .

Step-by-step explanation:

According to the Question

It is given that,

  • Product of two fraction = 27/98
  • Their LCM = 3/2

we have to calculate the their HCF .

As we know that ,

  • HCF × LCM = Product of two numbers

by putting the value we get

→ HCF × 3/2 = 27/98

→ HCF = 27/98 ÷ 3/2

→ HCF = 27/98 × 2/3

→ HCF = 9/49

  • Hence, their HCF is 9/49 .

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