Question

Please anyone answer this 6th question with explanation. I will make u brainliest...​

Answer 1

Step-by-step explanation:

As we can see the triangle ABC and triangle ADC are part of a rectangle in which the sides AC and BD are diagonal.

O is the centre of the rectangle.

As we know that all points (ie. A, B , C , D) are at equal distance from The center.

that's why A,B, and C are equidistant from O

Answer 2

Answer:

∆ABC is a right triangle of the triangle. O is the midpoint of the hypotenuse of a right triangle. A rectangle is drawn perpendicular to the right triangle and parallel to the ground by a dotted line, respectively.

Evidence / Prove that: The ears of the rectangle bisect each other.

Proof: Two triangles of the rectangle ABCD: AOD and BOC between, (i) <AOD = opposite <BOC (AC and BD intersect) (ii) <OAD = alternate <OCB (AD || BC and AC intersect) (iii ) <ODA = alternate <OBC (for exactly the same reason as above)

: .∆ AOD≈∆BOC. [Under A-A-A terms of uniformity]

.: Similar arms of a uniform triangle are equal to each other. OA = OC and OD = OB.

In this way we proved that O is equidistant from A,B and C.

Hope you understand.