please anyone answer this question
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carry out 2^28/2^29
therefore 2^28(2^2 +2^1 + 2^0)/2^29(2^2+2^1-2^0)
= 4+2+1/2(2+4-1)
= 7/2*5
=7/10
therefore 2^28(2^2 +2^1 + 2^0)/2^29(2^2+2^1-2^0)
= 4+2+1/2(2+4-1)
= 7/2*5
=7/10
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