Math, asked by sarswati2929, 1 year ago

please anyone can answer these 2 qyestion please........... ...​

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Answered by piyushkumar18
0

1 question answer:

given,

The equal sides are twice large then third side.

so, Let A, B, C is an isosceles triangle in which Non-equal side length=x cm

so, other two sides=2x (respectively )

perimeter of triangle=30cm(given)

perimeter of triangle=sum of all three sides.

=2x+2x+x cm=30cm

=5x=30cm

x=6cm

now,

value of 2x=2×6cm

=12cm.

Hence, 12,6,12 are the three sides of triangle.

q. 2ans;

perimeter of rectangle=40cm

given,

length of rectangle=4m less than 5 times breadth.

let the breadth of the rectangle =x m

question saying 5times =5x

length =5x-4m

perimeter=40cm

now changing 40 cm into m.

1m=100cm

1cm=1/100m

=40/100m

=0.4m.

perimeter of rectangle=2(l+b)

=0.4m=2(5x-4+5x)

0.4m=20x-8

4/10m=20x-8

20x=4/10+8

=4+80/10

=84/10

20x=84/10

x=42cm

now,

finding 5x value (breadth) =5×42=210m

length=210-4m

=206m

hope this helped you.

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