Question

please anyone explain me completing square method​

Answer 1

here is your answer mate:

first compare the given equation with ax^2 + bx + c

you will get the values of a b and c

now divide the whole equation with a and move the c/a term to the right

now the equation will be as

x^2 + bx/a = c/a

keep it as it is

now, find out what is the value of (b/2a)^2

add this value to bold LHS and RHS

now in LHS it will be of the form

ax^2 + bx^2 + 2ab = c/a + (b/2a)^2

reduce LHS into (a + b)^2 and solve RHS

taking squareroot on both the sides

you will get RHS in the form of + or - (something ... something)

equate LHS with both + RHs and -RHS

you will get the two values

hope this answer helps you buddy

i am sorry if it was not what you expected

but this is the best i can explain without a proper sum

please mark as brainliest :-)