Please anyone help me do this question and I will mark you as BRAINLIEST
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ani99ket:
tell me the problem
vecause the whole solution is already given
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take the number to be like 'xy0'.
according to the question
when number becomes 'yx0' then its value is less than original by 180.
therfore we can write the first number as
x*100 +y*10 + 0
and second number as
y*100 +x*10 +0
thus
y*100 +x*10 +0 = x*100 +y*10 +0 -180
you will get a equation
now according to second condition
number becomes "(x/2)0y" which equals
(x/2)*100 +0*10 +y which is less than the original by 454.
using the previous method get a equation as x and y.
now solve both the equation to get the answer.
according to the question
when number becomes 'yx0' then its value is less than original by 180.
therfore we can write the first number as
x*100 +y*10 + 0
and second number as
y*100 +x*10 +0
thus
y*100 +x*10 +0 = x*100 +y*10 +0 -180
you will get a equation
now according to second condition
number becomes "(x/2)0y" which equals
(x/2)*100 +0*10 +y which is less than the original by 454.
using the previous method get a equation as x and y.
now solve both the equation to get the answer.
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