please anyone help me in this please
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Answer:
a) (2y - 1) (2y - 1)
b) (2a - b)³
Step-by-step explanation:
a) 4y² - 4y + 1
= 4y² - (2 + 2)y + 1
= 4y² - 2y - 2y + 1
= 2y (2y - 1) - 1 (2y - 1)
= (2y - 1) (2y - 1).
b) 8a³ - b³ - 12a²b + 6ab²
= (2a)³ - (b)³ - 6ab (2a - b)
= (2a)³ - (b)³ - 3(2a)(b) [ 2a - b]
= (2a - b)³
{since, (a-b)³ = a³ - b³ - 3ab(a-b)}
Hope this answers your question. Thank you.
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