Please anyone help me in this question..
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given f(x)=cos(π2)x + cos(-π2)
=π=3.14
= π2=9
9<π<10 = π2=9
-10<π<-9 = 10
=f(x)=cos9x+cos10x
=f(π/2)=cos9(π/2)+cos10(π/2)
=f(π/2)=0 + (-1)
=f(π/2)=-1
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