Question

please anyone help me it's urgent yaar​

Answer 1

Given,

$\rightarrow$ PS = QR

$\rightarrow$ ∠1 = ∠2 , ∠3 = ∠4

$\rightarrow$ ∠ 1 + ∠3 = ∠2 + ∠4

$\rightarrow$ ∠SPQ = ∠RQP

$\rightarrow$ PQ = QP (Common side)

Hence, △SPQ ≅ △ RQP

(By SAS Congruence rule)

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∴ QS = PR (CPCT)

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*CPCT = Corresponding parts of Congruent triangles*

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Hope it helps✌