Question

Please anyone help to solve this Question​

Answer 1

Answer:

hope u get the answer

Step-by-step explanation:

if bases are same then ....

= (x^ a-b )^ a²+ab + b² . (x^ b-c ) ^ b² + bc+ c² . ( x^c-a) ^c²+CA+a²

= (x ^ a-b+b-c+c-a)^a²+ab+b²+ b²+BC+c²+c²+CA+a²

= (x^0) ^ 2a²+ 2b²+2c² +ab+BC+ca

= x^0

= 1

Answer 2

Answer:

LHS=RHS

Step-by-step explanation:

first open brackets

then u will get for first term

x^[acube+asquare b+ a b square]÷x^[asquareb+a b square+ b cube]

likewise open all then apply formula

$a {}^{m + n} = {a}^{m} \times {a}^{n}$

then for first term u will get {x^acube×x^a square b×x^absquare}÷{x^asquareb×absquare×bcube}

then it will cancel out to give 1 as ans.

I am sorry I would have uploaded the pic of ans but it is not loading

hope u will find it helpful

thanku