Please anyone send me the solution with explanation
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(a) we have , x+1/x =3
Therefore, (x-1/x)^2= (x+1)^2-4x × 1/x
= (3)^2-4 = 9-4 =5
x-1/x = sq.root 5.
(b) x^2+1/x^2 = (x+1/x)^2 - 2×x×1/x
= (3)^2-2 = 9-2 = 7
(c) x^4+1/x^4 = (x^2+1/x)^2 - 2 = (7)^2-2
= 49-2 = 47
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