Question

please anyone slove this I will try very time
bas iska answer batana hai kuch bhi nahi batana hai​

Answer 1

Explanation:

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Answer 2

Answer:

24 sq units

Explanation:

Let (3, 0), (4, 5), ( - 1, 4) and ( - 2, - 1) are the vertices A, B, C, D of a rhombus ABCD.

Length of diagonal A C  =[tex]\bf{ \sqrt{ [ 3 − ( − 1 ) ] ^{2} + ( 0 − 4 ) ^{2}}}{/tex]

= $\bf{\sqrt{16+16} = 4\sqrt{2}}$

Length of diagonal  B D = [tex]\bf{ \sqrt{ [ 4 − ( − 2 ) ] ^{2} + [ 5 − ( − 1 ) ] ^{2}}}[/tex]

= $\bf{\sqrt{36+36} = 6\sqrt{2}}$

Therefore, area of rhombus ABCD = $\bf{ \frac{1}{2} \times 4\sqrt{2} \times 6\sqrt{2}}$

= 24 square units