Please anyone solve it. ARGENT!!!!
ABCD is a cyclic quadrilateral. If AD || BC and B = 70°, find the other angles of ABCD.
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Answer: ∠A = 70° , ∠C = 110° and ∠D = 110°
Step-by-step explanation:
Since it is a cyclic quadrilateral the sum of opposite angles will be 180°.
So, ∠B + ∠D = 180
70 + ∠D = 180
∠D = 180 - 70 = 110°
Now, since AB║CD, then ∠B + ∠C = 180 (Interior angles)
70 + ∠C = 180
∠C = 180 - 70 = 110°
Now, sum of ∠A and ∠C will be 180° since they are opposite.
∠A + ∠C = 180
∠A + 110 = 180
∠A = 180 - 110 = 70°
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