Question

please anyone solve it. help me​

Answer 1

1) The equivalent capacitance in the circuit.

Given :-

V = 20V

C1 = 2 MICRO COULOMB

C2= 5 MICRO COULOMB

C3 = 3 MICRO COULOMB

Here capacitors c2 and c3 are in parallel connection and their total capacitance (C') is in series connection with c1

Therefore the total capacitance in the circuit is

Ceq = C' + C1

C' = (5 + 3) micro coulomb = 8 micro coulomb

$total \: capacitance \: = \frac{1}{2} + \frac{1}{8} = \frac{4}{8} + \frac{1}{8}$

$= \frac{5}{8}$

Now

$\frac{1}{total \: capacitance} = \frac{5}{8}$

Therefore The total capacitance io the circuit is 8/5 micro coulomb.

3) Charge on each capacitor

According to the equation

$c = \frac{q}{v}$

$q = cv$

Charge on the 1st capacitor

Q1 = C1 × V

= 2 × 10^-6 × 20

= 40 × 10^ -6 C

Do the same for the remaining 2 capacitors

the capacitance in

Q2 = C2 × V

× V = 5 × 10^-6 × 20

× 10^-6 × 20 = 5 × 10^ -6 C

Q3 = C3 × V

× V = 3 × 10^-6 × 20

× 10^-6 × 20 = 3 × 10^ -6 C

To find energy of capacitor, here we shall use the equation

$u \: = \frac{1}{2} \times c {v}^{2}$

put the values of 5 micro coulomb and 3 micro coulomb and you will get the answer and v = 20V