Math, asked by rare17dut, 8 months ago

please anyone solve the above problem.​

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Answered by student5649
1

</p><p> 4 tan 60° sec 30° +  \frac{</p><p>sin 31° sec 59° + cot 59° cot 31°}{ 8 sina 30° - tan2 45°</p><p>}

4 \times  \sqrt{3}  \times  \frac{2}{\sqrt{3} }  +  \frac{ \sin(31)  \times ( \cosec(90 - 59) )  + cot \: 59 \times  \tan(90 - 31) }{8 \times ( \frac{1}{2} ) \ -  {1}^{2}  }

8 +  \frac{ \sin(31)  \times \cosec \: (31)  + cot \: 59 \times  \ \cot(59) ) }{8 \times ( \frac{1}{2} ) \ -  {1}^{2}  }

8 +  \frac{ \ \: 1  + 1 }{8 \times ( \frac{1}{4} ) \ -  {1}^{2}}

8 +  \frac{ \ \: 2}{2 \ -  {1}^{2}}

8 +  \frac{ \ \: 2}{2 \ -  {1}^{}}

8 +  \frac{ \ \: 2}{1}

 \frac{8+ 2}{1}

\frac{10}{1}

=10

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