Math, asked by shreya931754, 9 months ago

please anyone solve these questions and if you do not know please don't answer useless answers otherwise I will report them​

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Answers

Answered by rajaman32
0

Step-by-step explanation:

1)

savings=576-432

=144

saving%=144*100/576

=25%

2)

no. of boys=540*100/30

=1800-540

=1260

3)

%age of copper=13*100/25

=52%

%age of zinc=7*100/25

=28%

%age of nickel=5*100/25

20%

hope it helps

Answered by pradnya250604
0

Answer:

Q1) Income= Rs 576

     Expenditure= Rs 432

     Savings= 576-432= Rs 144

     Percentage= 144/576 *100= 25%

Q2) Let the number of students in school be x

     No of boys= 70/100 *x= 7x/10

     ATQ, x= 540 + 7x/10= 5400 +7x

              10x= 5400+ 7x

              3x= 5400

               x=1800

    No. of boys= 7*1800/10= 7*180=1260

Q3) Parts of Copper = 13

     Parts of Zinc = 7

     Parts of Nickel = 5

     Total part of Alloy = 13+7+5 = 25

     Percentage of Copper(Cu) =( Value of Component/ Total Value x 100)%

                                                   = 13/25 x 100 %=52%

     Again,

     Percentage of Zinc(Zn) = 7/25 x 100 %=28%

     Now,

     Percentage of Nickel (Ni) = 5/25 x 100 %=20%

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