Question

Please anyone solve this​

Answer 1

Step-by-step explanation:

(p+q)-1×{(p-1)+(q-1)}=paqb

1/p+q×(1/p+1/q)=paqb

1/p+q×p+q/p+q=paqb

1/pq=paqb

(p-1)(q-1)=paqb

by comparing LHS and RHS

therefore a=-1 and b=-1

hence -1+(-1)+2=0

-1-1+2=0

-2+2=0

0=0

hence proved