Question

please anyone solve this...​

Answer 1

Let,

$v\propto E^xd^y\quad\longrightarrow\quad (1)$

Taking dimensions of each term,

$[v]= [E]^x[d]^y\\\\\\M^0L^1T^{-1}=(ML^{-1}T^{-2})^x(ML^{-3})^y\\\\\\M^0L^1T^{-1}=M^{x+y}L^{-x-3y}T^{-2x}$

Equating powers of corresponding terms on both sides,

$-2x=-1\quad\implies\quad x=\dfrac {1}{2}\\\\\\x+y=\dfrac {1}{2}+y=0\quad\implies\quad y=-\dfrac {1}{2}$

Then (1) becomes,

$v\propto E^{\frac {1}{2}}d^{-\frac {1}{2}}\\\\\\\large\boxed{v\propto\sqrt{\dfrac {E}{d}}}$

The proportionality symbol can be removed by multiplying with a constant.

Answer 2

Answer:

see the attachment

.

.

.

hope this helps you

please mark as brainliest

follow me