Question

please anyone solve this ​

Answer 1

Answer:

(i)

13

5

Since, 5=20×51

⇒ The denominator is in the form of 2m×5n, where m and n are non-negative integers.

So, the decimal form of

13

5

will be terminating type.

(ii)

2

11

Since, 11=20×50×111

⇒ The denominator is not in the form of 2m×5n, where m and n are non-negative integers.

So, the decimal form of

2

11

will be non-terminating recurring type.

(iii)

29

16

Since, 16=24×50

⇒ The denominator is in the form of 2m×5n, where m and n are non-negative integers.