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Step-by-step explanation:
(x+2)
3
=2x(x
2
−1)
⇒x
3
+2
3
+(3×x×2)(x+2)=2x
3
−2x(∵(a+b)
3
=a
3
+b
3
+3ab(a+b))
⇒x
3
+8+6x(x+2)=2x
3
−2x
⇒x
3
+8+6x
2
+12x=2x
3
−2x
⇒x
3
+8+6x
2
+12x−2x
3
+2x=0
⇒−x
3
+6x
2
+14x+8=0
Since the variable x in the equation −x
3
+6x
2
+14x+8=0 has degree 3, therefore, it is not of the form ax
2
+bx+c=0.
Hence, the equation (x+2)
3
=2x(x
2
−1) is not a quadratic equation.
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