Question

please anyone solve this . It' s important and urgent and wrong ans will give you report
Q).. If k is the ratio of the zeros of the polynomial 3 x²- 7 x + 2 then the value of 1/√2(k+1/k)½ is​

Answer 1

Answer:

$\sqrt{3/37}$

Step-by-step explanation:

3 x²- 7 x + 2 = 3 x² - x - 6x + 2 = x( 3x -1) - 2(3x-1) = (x-2)×(3x-1)

So, zeroes are 2 and 1/3 and k= (2/(1/3)) = 6

1/√2(k+1/k)½ = 1/ (√2 × $\sqrt{6+1/6}$ ) = 1/$\sqrt{12+1/3}$  =1/$\sqrt{37/3}$ = $\sqrt{3/37}$