Math, asked by subha9957, 1 year ago

please anyone solve this problem ​

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Answered by sarimkhan112005
0

Step-by-step explanation:

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Volume of rectangular parallel pipe =

l * b * h = 144 cc …………… (1)

SA = 2( lb + bh + hl ) = 192 cm²

Corner to corner diagonal AG = 13 cm

In the above image , in right tri ABC

AC² = l² + b²

In right tri ACG

AG² = AC² + GC² = l² + b² + h² = 13² = 169

Since, ( l + b + h )² = l² + b² + h² + 2( lb + bh + hl )

=> ( l+ b+ h)² = 169 + 192 = 361

=> l + b + h = 19 …………… (2)

By ( 1) & (2)

l b h = 144

& l + b + h = 19

Now, since prime factors of 144 =

2 x 2 x 2 x 2 x 3 x 3

Since 19 = 1+18

19 = 2+ 17

19 = 3 + 16

Or, 19 = 3 + 12 + 4 , we select 12 & 4 as 3,12,& 4 contain all the prime factors of 144

=> l x b x h = 12 x 4 x 3 = 144

& l + b + h = 12 + 4 + 3 = 19

So, 3 sides.. length = 12cm, breadth = 4 cm & height = 3cm

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subha9957: how can the numbers be randomly considered?
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