Question

please anyone solve this problem​

Answer 1

Answer:

c) 1/9

Step-by-step explanation:

$x = \frac{1}{3} \sec( \theta)$

$\frac{1}{x} = \frac{1}{3} \tan( \theta)$

$({x}^{2} - \frac{1}{ {x}^{2} } ) = \frac{1}{9} ( { \sec^{2} ( \theta) } - \tan^{2} ( \theta) )$

$= \frac{1}{9}$