Question

please anyone solve this problem
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Answer 1

here above answer for first onw

Answer 2

(i) let a= first term of an AP

and

let d= common difference of AP

Now, a = A+(p-1).d......(1)

b = B+(q-1).d......(2)

c = C+(r-1).d......(3)

subtract 2nd from 1st, 3rd from 2nd and 1st from 3rd..

We get,

a-b = (p-q).d......(4)

b-c = (q-r).d......(5)

c-a = (r-p).d......(6)

multiply 4,5,6 by c,a,b respectively, we get

a(q-r).d+b(r-p).d+c(p-r).d = 0[a(p-r)+b(r-p)+c(p-q)].d = 0

Now, since d is a common difference it should be no zero..

Therefore,

a(q-r)+b(r-p)+c(p-q)=0

I don't know that how to do second part ..so sorry about that...