Question

please anyone solve this problem...​

Answer 1

HOPE IT HELPS YOU....

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Answer 2

Given ,

Let the previous resistivity be P , length be l , area of cross section = A and radius be r .

A/q ,

(P × l)/A = 2 .

New

length = l/2

radius = r/2

Since , Area is inversely proportional to Length .

So , new area =( π × r/2×r/2)×2= A/2 .

Thus , new resistance = (P×l/2)/(A/2)= (P×L)/A = Previous resistance .

Hence , resistances will not change