Question

please anyone solve this question​

Answer 1

Answer:

Assume a square of side s, and a rectangle of sides a and b.

Since the perimeters are equal:

4s = 2(a+b)

or b = 2s-a.

ie, The sides of rectangle can be rewritten as [a] and [2s-a].

Their respective areas are

s² and (2s-a)a

If they are equal:

s² = 2sa - a²

s² -2sa + a² = 0

(s-a)² = 0

s=a

so only when s = a, both perimeter and area are equal.

This is the trivial case where square is also taken as rectanɡle.

In all other cases, no, area of rectanɡle and square are not equa

Step-by-step explanation:

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Answer 2

Answer:

No

Step-by-step explanation:

Because,

Permeter is measure of sides but,

Area is the measure of space taken by that figure or any thing.

ex. If length (l) of any square is 6cm then it's

Perimeter = 4l=4×6=24

And it's Area = l^2

=l×l

=6×6=

36sqcm

And if length (l) of any rectangle is 7 &

breadth (b) is 5 then it's

Perimeter =2(l+b)

=2(7+5)

=2×12

=24cm

And that of

Area = lb

= l×b

= 7×5

35 sqcm

So it is proved that square and rectangle having same perimeter don't have same area.

Hope you will get understand by this example

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