Question

please anyone solve this question ,then I will mark it as brainliest...​

Answer 1

Answer:

I think you have got your answer.

please mark it brainliest.

Answer 2

Answer:

$9 {c}^{2} + \frac{1}{ {9c}^{2} } = 66$

Step-by-step explanation:

$Given , \\ 3c - \frac{1}{3c} = 8 \\ Since, \\ {(3c - \frac{1}{3c} )}^{2} = 9 {c}^{2} + \frac{1}{ {9c}^{2} } - 2 \\ = > {(8)}^{2} = 9 {c}^{2} + \frac{1}{ {9c}^{2} } - 2 \\ = > 64 = 9 {c}^{2} + \frac{1}{ {9c}^{2} } - 2 \\ = >64 + 2 = 9 {c}^{2} + \frac{1}{ {9c}^{2} } \\ = > 9 {c}^{2} + \frac{1}{ {9c}^{2} } = 66$