Question

Please anyone solve this step by step !!
ax+by=c , bx+ay=1+c

Answer 1

let,

ax + by= c -----(1)

bx + ay = 1 + c -----(2)

multiplying (1) by b and (2) by a

so,

$bax + {b}^{2} y = bc$

$bax + {a}^{2} y = a + ac$

by elimination method,

$bax + {b}^{2} y = bc$

$bax + {a}^{2} y = a + ac$

(-) (-) (-)

-------------------------------------------

$0 + y( {b}^{2} - {a}^{2} ) = bc - a - ac \\ y( {b}^{2} - {a}^{2} ) = c(b - a) - a$

so,

$y = \frac{ c(b - a) - a}{ {b}^{2} - {a}^{2} }$

and from (1)

$x = \frac{c - by}{a}$

so,

$x = \frac{c - b( \frac{c(b - a) - a}{ {b}^{2} { - a}^{2} } )}{a}$

$x = \frac{ \frac{c - {b}^{2}c + bac + ab }{ {b}^{2} - {a}^{2} } }{a}$

$x = \frac{c - {b}^{2}c + bac + ab}{ {b}^{2} - {a}^{2} } \times \frac{1}{a} \\ x = \frac{c - {b}^{2} c + bac+ ab}{a {b}^{2} - {a}^{3} }$

so a above are the values of x and y

pls. mark BRAINLIEST.

Answer 2

ax+by=c... (1)

bx+ay=1+c... (2)

Putting (1) eq. into (2) eq.

bx+ay=1+ax+by

bx-ax+ay-by=1

x(b-a) +y(a-b) =1

x+y=1

hope it will help you out...

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