Question

please anyone tell me those who will tell me i will thank ful to him​

Answer 1

Answer:

LHS=

${( \frac{ {x}^{a} }{ {x}^{b} }) }^{ \frac{1}{ab} } . {( \frac{ {x}^{b} }{ {x}^{c} }) }^{ \frac{1}{bc} }. {( \frac{ {x}^{c} }{ {x}^{a} }) }^{ \frac{1}{ac} } \\ = {x}^{(a - b)( \frac{1}{ab}) } .{x}^{( b - c)( \frac{1}{bc}) }.{x}^{(c - a )( \frac{1}{ac}) } \\ = {x}^{ (\frac{a}{ab} - \frac{b}{ab} ) } .{x}^{ (\frac{b}{bc} - \frac{c}{bc} ) } .{x}^{ (\frac{c}{ac} - \frac{a}{ac} ) } \\ = {x}^{(a - b)} .{x}^{(b - c)} .{x}^{(c - a)} \\ = {x}^{(a - b + b - c + c - a)} \\ = {x}^{0} \\ =1 \\ = rhs$

=RHS

Hence proved

I hope this will help you