Question

Please anyone tell the anwer

Answer 1

Given :

• Length of Rectangle is 3 cm more than its breadth .
• Perimeter of Rectangle is 34 cm .

To Find :

• Length and Breadth of Rectangle .

Solution :

$\longmapsto\tt{Let\:Breadth\:be=x}$

As Given that Length of Rectangle is 3 cm more than its breadth . So ,

$\longmapsto\tt{Length=x+3}$

Using Formula :

$\longmapsto\tt\boxed{Perimeter\:of\:Rectangle=2(l+b)}$

Putting Values :

$\longmapsto\tt{34=2(x+3+x)}$

$\longmapsto\tt{34=2(2x+3)}$

$\longmapsto\tt{\cancel\dfrac{34}{2}=2x+3}$

$\longmapsto\tt{17-3=2x}$

$\longmapsto\tt{14=2x}$

$\longmapsto\tt{\cancel\dfrac{14}{2}=x}$

$\longmapsto\tt\bf{7=x}$

Value of x is 7 .

Therefore :

$\longmapsto\tt{Length\:of\:Rectangle=7+3}$

$\longmapsto\tt\bf{10\:cm}$

$\longmapsto\tt{Breadth\:of\:Rectangle=x}$

$\longmapsto\tt\bf{7\:cm}$

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VERIFICATION :

$\longmapsto\tt{34=2(x+3+x)}$

$\longmapsto\tt{34=2(7+3+7)}$

$\longmapsto\tt{34=2(17)}$

$\longmapsto\tt\bf{34=34}$

HENCE VERIFIED

Answer 2

Answer:

Given :-

• The length of a rectangle is 3 cm more than its breadth and its perimeter is 34 cm.

To Find :-

• What is the length and breadth respectively

Formula Used :-

$\small\purple{\underline{{\boxed{\textbf{Perimeter\: =\: 2(Length\: +\: Breadth)}}}}}$

Solution :-

Let, the breadth be x

And, the length will be x + 3

According to the question by using the formula we get,

⇒ 2(x + 3 + x) = 34

⇒ 2x + 6 + 2x = 34

⇒ 2x + 2x = - 6 + 34

⇒ 4x = 28

⇒ x = $\sf\dfrac{\cancel{28}}{\cancel{4}}$

➠ x = 7

Hence, the required length and breadth will be,

❐ Length = x + 3 = 7 + 3 = 10 cm

❐ Breadth = x = 7 cm

$\therefore$ The length and breadth of a rectangle is 10 cm and 7 cm respectively.

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