Math, asked by ranjitsinghhk46, 3 days ago

please ask me step by step solution

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Answered by mahaswetabanerjee200
0

Answer:

9a²+12a+4

9a²+(6a+6a)+4. [middle term factor]

9a²+6a+6a+4

3a(3a+2)+2(3a+2)

(3a+2)(3a+2)

hope it helps!!!

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Answered by diwanamrmznu
6

GIVEN★

 = 9a {}^{2}  + 12a + 4

find ★

  • given eq factorise

EVALUTION★

  •  = 9a {}^{2} + 12a + 4 \\  \\  \\ can \: be \: this \: written  \: as \\  \\  \\  = 9a {}^{2} + 6a + 6a + 4  \\  \\  \\   take  \: common \: 3a \:  \: and \: 2 \\  \\  \\  = 3a(3a + 2) + 2(3a + 2) \\  \\  \\  = (3a + 2) (3a + 2)

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I hope it helps you

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