Question

please assume p and as a and b

Answer 1

Answer:

$\sf \implies \displaystyle \int \dfrac{3x^{2} + 1}{(x + 1)^{3}(x - 1)^{3} } dx.$$\huge\mathcal{\pink{A}}\huge\mathcal{\purple{N}}\huge\mathcal{\green{S}}\huge\mathcal{\blue{W}}\huge\mathcal{\red{E}}\huge\mathcal{R}$$\sf \implies \displaystyle \int \dfrac{3x^{2} + 1}{(x + 1)^{3}(x - 1)^{3} } dx.$$\huge\mathcal{\pink{A}}\huge\mathcal{\purple{N}}\huge\mathcal{\green{S}}\huge\mathcal{\blue{W}}\huge\mathcal{\red{E}}\huge\mathcal{R}$$\sf \implies \displaystyle \int \dfrac{3x^{2} + 1}{(x + 1)^{3}(x - 1)^{3} } dx.$$\huge\mathcal{\pink{A}}\huge\mathcal{\purple{N}}\huge\mathcal{\green{S}}\huge\mathcal{\blue{W}}\huge\mathcal{\red{E}}\huge\mathcal{R}$$\sf \implies \displaystyle \int \dfrac{3x^{2} + 1}{(x + 1)^{3}(x - 1)^{3} } dx.$$\huge\mathcal{\pink{A}}\huge\mathcal{\purple{N}}\huge\mathcal{\green{S}}\huge\mathcal{\blue{W}}\huge\mathcal{\red{E}}\huge\mathcal{R}$$\huge\mathcal{\pink{A}}\huge\mathcal{\purple{N}}\huge\mathcal{\green{S}}\huge\mathcal{\blue{W}}\huge\mathcal{\red{E}}\huge\mathcal{R}$$\sf \implies \displaystyle \int \dfrac{3x^{2} + 1}{(x + 1)^{3}(x - 1)^{3} } dx.$$\huge\mathcal{\pink{A}}\huge\mathcal{\purple{N}}\huge\mathcal{\green{S}}\huge\mathcal{\blue{W}}\huge\mathcal{\red{E}}\huge\mathcal{R}$$\sf \implies \displaystyle \int \dfrac{3x^{2} + 1}{(x + 1)^{3}(x - 1)^{3} } dx.$$\huge\mathcal{\pink{A}}\huge\mathcal{\purple{N}}\huge\mathcal{\green{S}}\huge\mathcal{\blue{W}}\huge\mathcal{\red{E}}\huge\mathcal{R}$$\sf \implies \displaystyle \int \dfrac{3x^{2} + 1}{(x + 1)^{3}(x - 1)^{3} } dx.$$\huge\mathcal{\pink{A}}\huge\mathcal{\purple{N}}\huge\mathcal{\green{S}}\huge\mathcal{\blue{W}}\huge\mathcal{\red{E}}\huge\mathcal{R}$$\sf \implies \displaystyle \int \dfrac{3x^{2} + 1}{(x + 1)^{3}(x - 1)^{3} } dx.$$\huge\mathcal{\pink{A}}\huge\mathcal{\purple{N}}\huge\mathcal{\green{S}}\huge\mathcal{\blue{W}}\huge\mathcal{\red{E}}\huge\mathcal{R}$$\sf \implies \displaystyle \int \dfrac{3x^{2} + 1}{(x + 1)^{3}(x - 1)^{3} } dx.$$\huge\mathcal{\pink{A}}\huge\mathcal{\purple{N}}\huge\mathcal{\green{S}}\huge\mathcal{\blue{W}}\huge\mathcal{\red{E}}\huge\mathcal{R}$$\sf \implies \displaystyle \int \dfrac{3x^{2} + 1}{(x + 1)^{3}(x - 1)^{3} } dx.$$\huge\mathcal{\pink{A}}\huge\mathcal{\purple{N}}\huge\mathcal{\green{S}}\huge\mathcal{\blue{W}}\huge\mathcal{\red{E}}\huge\mathcal{R}$$\sf \implies \displaystyle \int \dfrac{3x^{2} + 1}{(x + 1)^{3}(x - 1)^{3} } dx.$$\huge\mathcal{\pink{A}}\huge\mathcal{\purple{N}}\huge\mathcal{\green{S}}\huge\mathcal{\blue{W}}\huge\mathcal{\red{E}}\huge\mathcal{R}$$\sf \implies \displaystyle \int \dfrac{3x^{2} + 1}{(x + 1)^{3}(x - 1)^{3} } dx.$$\huge\mathcal{\pink{A}}\huge\mathcal{\purple{N}}\huge\mathcal{\green{S}}\huge\mathcal{\blue{W}}\huge\mathcal{\red{E}}\huge\mathcal{R}$$\sf \implies \displaystyle \int \dfrac{3x^{2} + 1}{(x + 1)^{3}(x - 1)^{3} } dx.$$\huge\mathcal{\pink{A}}\huge\mathcal{\purple{N}}\huge\mathcal{\green{S}}\huge\mathcal{\blue{W}}\huge\mathcal{\red{E}}\huge\mathcal{R}$$\sf \implies \displaystyle \int \dfrac{3x^{2} + 1}{(x + 1)^{3}(x - 1)^{3} } dx.$$\huge\mathcal{\pink{A}}\huge\mathcal{\purple{N}}\huge\mathcal{\green{S}}\huge\mathcal{\blue{W}}\huge\mathcal{\red{E}}\huge\mathcal{R}$$\sf \implies \displaystyle \int \dfrac{3x^{2} + 1}{(x + 1)^{3}(x - 1)^{3} } dx.$$\huge\mathcal{\pink{A}}\huge\mathcal{\purple{N}}\huge\mathcal{\green{S}}\huge\mathcal{\blue{W}}\huge\mathcal{\red{E}}\huge\mathcal{R}$$\sf \implies \displaystyle \int \dfrac{3x^{2} + 1}{(x + 1)^{3}(x - 1)^{3} } dx.$