Question

please be fast request
the perimeter of a angled triangle is 72cm and its area is 216 cm2 find the sum of a length of its perpendicular sides

Answer 1

let the perpendicular sides be denoted by B and H
area=1/2*B*H=216 therefore BH=432
now by phythagorous triplet we have
B^2+H^2=hypotenuse^2
(B+H)^2-2BH=x^2

here we have B+H+x=72 therefore B+H=72-x
now substituting in above equation
(72-x)^2-864=x^2
5184+144x-864=0 (x^2 cancels)
therefore we get x=30

hence B+H=72-30=42
hence 42 is the answer
hope it helps you