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Dear friend,
In right triangle PCD,
PC = √(PD^2+CD^2)=√(12^2+16^2)= = √400 = 20 m
Now in right triangle APC,
AP = √(AC^2-
PC^2)= √(52^2-20^2)= 48 m
Again, in right triangle ABP,
AB = √(AP^2-BP^2)= √(48^2-16^2)= 45.25 m
AP = 48 m
AB = 45.25 m
Hope it helps
In right triangle PCD,
PC = √(PD^2+CD^2)=√(12^2+16^2)= = √400 = 20 m
Now in right triangle APC,
AP = √(AC^2-
PC^2)= √(52^2-20^2)= 48 m
Again, in right triangle ABP,
AB = √(AP^2-BP^2)= √(48^2-16^2)= 45.25 m
AP = 48 m
AB = 45.25 m
Hope it helps
Answered by
0
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