Question

please briefly explain me​

Answer 1

$\huge\bold{\gray{\sf{Answer:}}}$

$\bold{Explanation:}$

=>Let 'X' be divided with $\sf\bigg [ { \bigg({ \dfrac{ - 5}{7}\bigg) }^{2}\bigg ]}^{3}$ to obtain

$\sf{ \bigg(\dfrac{ - 5}{7}\bigg) }^{6}$

$\huge \sf\bold{\boxed{{ \bigg({a}^{m}\bigg) }^{n} = {a}^{mn} }}$

$\sf\bigg [ { \bigg({ \dfrac{ - 5}{7}\bigg) }^{2}\bigg ]}^{3}$ =>$\sf{ \bigg(\dfrac{ - 5}{7}\bigg) }^{6}$

$=>\sf\dfrac{ {\bigg( \dfrac{ - 5}{7}\bigg) }^{6} }{x} = {\bigg( \dfrac{ - 5}{7}\bigg) }^{ - 6}$

$=>\sf \dfrac{ { \bigg(\dfrac{ - 5}{7}\bigg) }^{6} }{ {\bigg( \dfrac{ - 5}{7}\bigg) }^{ - 6} }$

$=>\sf{\bigg (\dfrac{ - 5}{7}\bigg) }^{6 - ( - 6)}$

$=>\sf {\bigg (\dfrac{ - 5}{7} \bigg)}^{12}$

$\therefore\sf {\bigg (\dfrac{ - 5}{7} \bigg)}^{12}$ be divided with $\sf {\bigg (\dfrac{ - 5}{7} \bigg)}^{6}$ to get $\sf {\bigg (\dfrac{ - 5}{7} \bigg)}^{-6}$

$\huge\bold{Check:}$

$=>\sf \dfrac{ { \bigg(\dfrac{ - 5}{7}\bigg) }^{6} }{ {\bigg( \dfrac{ - 5}{7}\bigg) }^{ 12} }$

Here ,we see that bases are same so powers gets substracted.

$=>\sf {\bigg (\dfrac{ - 5}{7} \bigg)}^{6-12}$$=\sf {\bigg (\dfrac{ - 5}{7} \bigg)}^{-6}$

Answer 2

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