Question

please c solve it. and don't try to give irrelevant answers.​

Answer 1

Answer:

4800cm²

Step-by-step explanation:

The total figure can be split into 3 parts:

ΔABF , ΔCED, Trapezium BFEC

So we need to find individual areas and add

i) ΔABF

Consider base as BF =50+50 =100cm

So height = 80-60 = 20cm

Area of ΔABF =0.5× base ×height = 0.5 × 100×20 =100×10 =1000cm²

ii) ΔCED

Consider base as CE =30+30 =60cm

Here, height =  20cm

Area of ΔCED =0.5× base ×height = 0.5 × 60×20 =60×10 =600cm²

iii) Trapezium BFEC

Area of a trapezium = 0.5 × (sum of parallel sides) × height

Here parallel sides are BF and CE

Sum of parallel sides = BF+CE =100+60 =160cm

Here height = 60-20 =40

Area = 0.5×40×160 =160×20 = 3200cm²

Total area = 1000cm²+600cm²+3200cm² = 4800cm²