Please can anybody solve this sum in a lucid (easy) method.
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Consider a right angled triangle ,right angled at C
∴ Cos A = AC/AB
Cos B = BC/AB
It is given that CosA = CosB
⇒AC/AB = BC/AB
AC=BC
By applying the property of angles opposite to equal sides are equal
∠A = B
Hence proved !!!
Hope it helps...:)
∴ Cos A = AC/AB
Cos B = BC/AB
It is given that CosA = CosB
⇒AC/AB = BC/AB
AC=BC
By applying the property of angles opposite to equal sides are equal
∠A = B
Hence proved !!!
Hope it helps...:)
niyamee:
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