please ,can anyone answer this
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hi friend this is your ans plz follow me hope this helpful for you
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given that
<1=<2
:.<ABG=<DCF
BC=CE
since <ABC= straight line =180 degree
<ABG+<GBC=180 degree-------(I)
again
<FEC=straight line=180 degree
<DEC+<DEF=180 degree----------(ii)
from (I) and (ii)
<ABG+<GBC= <DEC+<DEF
<ABG+<GBC =<DEC+<ABG (<ABG=<DCF)
:.<GBC=<DEC---------(iii)
Now, we have
From ∆GCB and ∆DCE-
BC=CE (given)
<GBC=<DEC ( from iii )
<GCB=<DCE
therefore∆GCB=~∆DCE
I hope help you....
<1=<2
:.<ABG=<DCF
BC=CE
since <ABC= straight line =180 degree
<ABG+<GBC=180 degree-------(I)
again
<FEC=straight line=180 degree
<DEC+<DEF=180 degree----------(ii)
from (I) and (ii)
<ABG+<GBC= <DEC+<DEF
<ABG+<GBC =<DEC+<ABG (<ABG=<DCF)
:.<GBC=<DEC---------(iii)
Now, we have
From ∆GCB and ∆DCE-
BC=CE (given)
<GBC=<DEC ( from iii )
<GCB=<DCE
therefore∆GCB=~∆DCE
I hope help you....
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