Question

please can anyone can simplify this question number 3​

Answer 1

$\underline{\mathbf{\huge{Question}}}$

$\mathbf{\frac{243 \times {x}^{3} \times {y}^{ - 5} }{81 \times {x}^{ - 2} \times {y}^{2} } }$

$\underline{\mathbf{\huge{Answer}}}$

$\mathbf{\frac{\cancel{243} \times {x}^{3} \times {y}^{ - 5} }{\cancel{81} \times {x}^{ - 2} \times {y}^{2} } } \\ \\ \mathbf{\frac{{3} \times {x}^{3} \times {y}^{ - 5} }{ {x}^{ - 2} \times {y}^{2} } }$

According to law of Exponent.

If ,

a^x÷a^y

=a^x-y

$\mathbf{3\times {x}^{3 - ( - 2)} \times {y}^{ - 5 - 2} } \\ \\\mathbf{3\times {x}^{(3 + 2)} \times {y}^{ - 7} } \\ \\\mathbf{3\times {x}^{5} \times {y}^{ - 7} }$

$\boxed{\mathbf{\huge{Answer=3\times {x}^{5} \times {y}^{ - 7}}}}$

Since,

a^-x=1/a^x

Then=y^-7=1/y^7

Answer Can Be also

$\mathbf{3\times {x}^{5} \times\:\frac{1}{{y}^{7}}}$

$\boxed{\mathbf{\huge{Answer=\frac{3\times{x}^{5}}{{y}^{7}}}}}$