please can anyone find x and y in the following questions. only questions 18 and 20
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for the first one the answer is 180-50=130°=y.
plsss write properly (<ABC). so that I can solve for x also.
2)we know that the tangent to the circle is always perpendicular to the center.<ABC=90°.
<ACD=180-(65+90)=180-155=25°. and <OEC=<OCE=25°(radii).
then <EOC=180-(50)=130°.and <BOE=180-<EOC=50°.
and thus , x=180-(90+50)=40°.
plsss write properly (<ABC). so that I can solve for x also.
2)we know that the tangent to the circle is always perpendicular to the center.<ABC=90°.
<ACD=180-(65+90)=180-155=25°. and <OEC=<OCE=25°(radii).
then <EOC=180-(50)=130°.and <BOE=180-<EOC=50°.
and thus , x=180-(90+50)=40°.
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