Question

Please can anyone give me the answer quickly, it's very urgent??​

Answer 1

Step-by-step explanation:

GIVEN

$\sec\alpha = \frac{13}{12}$

So wkt

sec=1/cos

$\cos \alpha = \frac{12}{13}$

SO WKT COS WILL BE ADJACENT UPON HYPOTENUSE

SO HYPOTENUSE WILL BE 13 CM AND ANOTHER WILL BE 12 CM

SO BY PHYTAGOROS THEROM

THE OTHER SIDE WILL BE 5 CM

HENCE THE REQUIRED OTHER RATIOS WILL BE

$\sin \alpha = \frac{5}{13}$

$\cos\alpha = \frac{12}{13}$

$\tan \alpha = \frac{5}{12}$

$\cot\alpha = \frac{12}{5}$

$\cosec \alpha = \frac{13}{5}$

PLZ MARKS AS BRAINLIEST ANSWER FOR MY HARD WORK

Answer 2

Hello buddy

Answer:

Sin theta is 5/13

Cos theta is 12/13

Tan theta is 5/12

Cosec theta is 13/5

Cot theta is 12/5

By Pythagoras theorem

Opposite is 5

Mark My answer as brainliest

I hope it helped you dude