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r = 20cm
theta = 90 degree
area of sector = theta/360 πr2
= 90/360 ×22/7 × 20 ×20
= 1/4 ×22/7 ×20 × 20
= 2200/7
314.2 cm2
area of triangle = 1/2 × base ×height
= 1/2 × 20 ×20 ( base and height both are r ) = 200 cm2
Area of minor segment = 314.2 - 200 = 114.2 cm2
major segment = area of circle - 114.2
= π r2 - 114.2
=22/7 ×20 × 20 -114.2
= 1142 .94 cm2
hope this helps...pls leave a like
theta = 90 degree
area of sector = theta/360 πr2
= 90/360 ×22/7 × 20 ×20
= 1/4 ×22/7 ×20 × 20
= 2200/7
314.2 cm2
area of triangle = 1/2 × base ×height
= 1/2 × 20 ×20 ( base and height both are r ) = 200 cm2
Area of minor segment = 314.2 - 200 = 114.2 cm2
major segment = area of circle - 114.2
= π r2 - 114.2
=22/7 ×20 × 20 -114.2
= 1142 .94 cm2
hope this helps...pls leave a like
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