please can anyone solve 24,25,26 questions
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★ BINOMIAL EXPANSION ★
In first approach , we've made the sum of 5th and 6th term equal to zero , which further reduced to gives the final answer
In second approach , we've found the nth term then , proceeded with finding the coefficients of x⁷ and x⁻⁷ respectively ,
At last approaches in question , middle term of any binomial expansion is equal to n/2 + 1 if n is even , and n + 1 / 2 and n + 3 / 2 will be the two middle terms of the binomial expansion if n is odd , same as implied above
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In first approach , we've made the sum of 5th and 6th term equal to zero , which further reduced to gives the final answer
In second approach , we've found the nth term then , proceeded with finding the coefficients of x⁷ and x⁻⁷ respectively ,
At last approaches in question , middle term of any binomial expansion is equal to n/2 + 1 if n is even , and n + 1 / 2 and n + 3 / 2 will be the two middle terms of the binomial expansion if n is odd , same as implied above
★✩★✩★✩★✩★✩★✩★✩★✩★✩★✩★
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