please can anyone solve I'll mark brainliest
Attachments:
Answers
Answered by
2
Since AD=AC therefore ∠ADC=∠ACD
now ∠C = ∠ACD=65° therefore∠ ADC=65°
∠DAC=180°-(65°+65°)
Or, DAC=180°-130°=50°
∠ADB(ext. angle)=∠DAC +∠ADC(int. opp. angles)=65°+65°=130°
∠BAD=180°-(130°+40°)=180°-170°=30°
We know greater angle has greater side opposite to it. hence the sides of ABD in ascenfing order are BD, AD,AB
now ∠C = ∠ACD=65° therefore∠ ADC=65°
∠DAC=180°-(65°+65°)
Or, DAC=180°-130°=50°
∠ADB(ext. angle)=∠DAC +∠ADC(int. opp. angles)=65°+65°=130°
∠BAD=180°-(130°+40°)=180°-170°=30°
We know greater angle has greater side opposite to it. hence the sides of ABD in ascenfing order are BD, AD,AB
Similar questions