Question

Please can anyone solve question 25 asap? Will mark you brainliest, thanks :D

Answer 1

Answer:

Step-by-step explanation:

In ΔPRQ,

PQ=PR

∠PQR=∠PRQ

so, x+x+30°=180°

2x=150°

x=75°

Since RS║QR,Alternate angles are equal

∴∠SRQ=∠RQP=75°

Co-incident angles are supplementary,

∠PRS+∠RSQ=180°

150°+∠RSQ=180°

∠RSQ=30°

InΔ RQS,

75°+30°+∠RQS=180°

∠RQS=180°-105°

⇒∠RQS=75°