Math, asked by sutharpraveena414, 11 months ago

Please can I get an answer to this question.
It's urgent because tmrw is my Maths exam. ​

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Answers

Answered by rupaliparida2972
1

Hope it helps u and solves ur problem.

#rupaliparida

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Answered by Anonymous
0

Answer

Identity to be used:

a^3 + b^3 + c^3 - 3abc = (a + b + c)(a^2 + b^2 + c^2 - ab - bc - ca)

(ab + bc + ca - a^2 - b^2 - c^2)/(3abc - a^3 - b^3 - c^3)

=> -(a^2 + b^2 + c^2 - ab - bc - ca)/-(a^3 + b^3 + c^3 - 3abc)

Minus sign cancelled

=> (a^2 + b^2 + c^2 - ab - bc - ca)/(a + b + c)(a^2 + b^2 + c^2 - ab - bc - ca)

=> 1/(a + b + c)

=> 1/(2+3+4)

=> 1/(9)

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