Question

Please can someone give me solution of this please I will give u thanks!!​

Answer 1

Step-by-step explanation:

First side = (3x²-5y²)

Second side = (6x²-4y)

Perimeter of a rectangle = 2(l+b)

= 2{(3x²-5y²)+(6x²-4y)}

This is the furthest we can move

Hope this helps :)

Answer 2

$\huge \star \underline \pink{AnsWeR}$

First side = 3x²-5y²

second side = 6x²-4y.

perimeter = 2(l+b)

= 2(3x²-5y²+6x²-4y)

= 2(9x²-5y²-4y)