please can someone help me solve this question
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in triangle ANB and AMC
AB=AC (given
BM=CN (given
angle A=angle A(common angle
triangle ABN~ACM(by SAS rule
AM=AN (by CPCT
also BN=CM (CPCT
in triangle BMC and CNB
BC=BC (common side
CM=BN( proved above
BM=CN ( given
triangle BMC ~CNB( by SSS rule
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