Question

please can someone solve this question step by step​

Answer 1

Answer:

Here you go...!!!

Hope this will help you.

Answer 2

Answer:

given a-1/a=4..............(I)

and ais not equal to zero

(a-1/a)2= a2 + 1/a2 -2×a×1/a

(4)2= a2 +1/a2 -2

16+2= a2 +1/a2

18= a2 + 1/a2.............(I)

if we take

(a2 -1/a2)2 = a4 +1/a4 -2×a2×1/a2

(18)2= a4 + 1/a4 -2( fromii)

324+2=a4 + 1/a4

326= a4 +1/a4

similarly,if we take

(x-1/x)3 = a3-1/a3- 3 x×1/x(x+1/x)

(4)3 = a3-1/a3 +3× 4( from eq I)

64+12=a3 -1/a3

76= a3-1/a3